Question

Det nr x, y si z stiind ca sunt direct proportionale cu nr 0, 25; 0,(3); 0,5 si ca xy+xz+yz= 3xyz

Answer 1

0,25x=0, (3)y=0,5 z
25x/100=3y/9=5z/10
x/4=y/3=z/2=k
x=4 k
y= 3 k
z= 2 k
xy+xz+yz=3 xyz
12 k^2+8 k^2+6 k^2 =3×24 k^3
26 k^2 = 72 k^3
26 = 72 k
13 = 36 k
k =13/36
x= 4×13/36=13/9
y = 3×13/36=13/12
z= 2×13/36 =13/18