Question

Determin masa de sulfat de sodiu ce contine 32g Oxigen;6,022×10(la puterea 23)Sodiu;6.4 kg Sulf;11.5 g de sodiu

Answer 1

n,O2= m/M=>32g/32g/mol= 1mol O2---> n= 2mol O
n,Na= N/ N,A=> n= 6,021x10²³atomi/ 6,023x10²³at/mol= 1 molNa
n,S= m/M=> 6400g/ 32g/mol = 200molS
n,Na= m/M => 11,5g/23g/mol=0,5mol
Na2SO4
M= (2X23gNa +32gS+4X16gO)/mol=142g/mol

142g sare.......2molNa.......1molS.......4molO
142/2......................................................2molO
142/2.................1molNa
142X200...............................200molS
142/4.................0,5molNa