Question

Determina a,b,c, stiindca {a:b=3rest9;a:c=3;a+b+c=62

Answer 1

a:b=3,rest 9 , a=3b+9 , 3b= a-9
a:c=3, a =3c
a+b+c=62 / * 3 , 3a+3b+3c=186
Dupa inlocuire:
3a+a-9+a=186 , 5a=186+9, 5a= 195 , deci a =39 si de aici ies si b si c

Answer 2

a=3b+9
a=3c   rezulta c=a/3=(3b+9)/3=3(b+3)/3=b+3
deci c=b+3
a+b+c=62
3b+9+b+b+3=62
5b+12=62
5b=62-12
b=50/5
b=10
c=b+3=10+3=13
c=13
a=3b+9=3x10+9=39
a=39
39+13+10=62