Question

determina cel mai mic nr nat care impartit la 7 da rest 5 si impartit la 11 da rest 9

Answer 1

a : 7 = x rest 5 ==> a = 7x + 5 |+2
a : 11 = y rest 9 ==> a = 11y + 9 |+2

a + 2 = 7×(x+1)
a + 2 = 11 ×(y+1)

a + 2 = 7 × 11
a + 2 = 77
a = 77 - 2
a = 75 (numarul cautat)

Verificare:
75 : 7 = 10 rest 5
75 : 11 = 6 rest 9