Question

determina, după modelul dat, compoziția procentuală pentru fiecare dintre substantele de mai jos, pornind de la masa molara​

Answer 1

Răspuns:

Explicație:

MNO= 14 + 16=30--------> 30g/moli

30g NO---------14gN---------16gO

100g-----------------x------------------y

x= 100.14 : 30 =46,66 % N

y= 100.16 : 30  = 53,34% O

MK2SO4= 2.39 + 32 + 4.16=174--------> 174g/moli

174g K2SO4--------78gK---------32gS---------64g O

100g---------------------x-----------------y----------------z

x= 100 . 78 : 174 =44,82% K

y=100  . 32 : 174 =1 8 , 40 % S

z= 100 .64 : 174 =36,78 % O

MCaCl2=40 + 2.35,5=111--------> 111g/moli

111g CaCl2---------40gCa--------71g Cl

100g---------------------x------------------y

x= 100 . 40 : 111 = 36,04 % Ca

y= 100 . 71 : 111 = 63,96% Cl

MMg(OH)2 =24 + 2.16 +2= 58-------> 58g/moli

58g Mg(OH)2----------24g Mg--------32g O---------2gH

100g--------------------------x-------------------y---------------z

x= 100 . 24 : 58 = 41,38%Mg

y=100. 32 : 58 = 55,17%O

z= 100 . 2 : 58 = 3,45% H