Question

Determina formula moleculara a unei substante organice care are raportul de masa C:H:O=6:1:8 si masa molara 60g/mol.

Answer 1

C=6/12=0,5 moli => 1 atom C

H=1/1=1 mol => 2 atomi H

O=8/16=0,5 moli  => 1 a tom O

F.B => (CH2O)n = 60 => 12n+2n+16n=60 => 30n=60 => n=2 

F.M => C2H4O2 -> acid acetic -> CH3-COOH