Question

Determina masa clorurii de hidrogen cu volumul 6,72 l

Answer 1

clorura de hidrogen = HCl

niu = nr moli = masa/miu (masa moleculara)

niu = V/Vm (Vm = volumul molar = 22,4, L in c.n.)

=> masa/miu = V/Vm

miu(HCl) = 1x1+35,5x1 = 36,5 g/mol

=> m = miuxV/Vm = 36,5x6,72/22,4 = 10,95 g HCl