Question

determina masa de dioxid de carbon ce contine aceeasi cantitate de oxigen ca si 5moli apa

Answer 1

nr moil= masa/masa molara
n=m/M⇒ m=n *M= 5*18=90g H2O
M H2O=2*1+16=18 g/mol
In 18gH2O...............16gO
    90gH2O................xgO
x= 90*16/ 18=80gO se gasesc in 90gH2O
M CO2= 12+2*16=44g/mol
In 44g CO2................(2*16)gO
    y   gCO2.................80      gO
y= 44*80/ 32= 110g CO2