Question

Determina masa de NaOH care reactioneaza xu 2,52 g de amestec echimolecular de fenol si metanol.

Answer 1

C6H5-OH + NaOH = C6H5-ONa + H2O
m amestec = n fenol*M fenol + n metanol*M metanol
M fenol = 94 g/mol
M metanol = 32 g/mol
n fenol = n metanol = x
2,52 = x*94+x*32
x = 0,01166 moli
=> n fenol = 0,01166 moli
M NaOH = 40 g/mol
1 mol fenol.........40 g NaOH
0,01166 moli fenol.............a
a = 0,4666 g NaOH