Question

Determina masurile a doua unghiuri suplementare ,care sunt invers proportionale cu0,(3),respectiv0,(6)

Answer 1

0,(3)=3/9=1/3
0,(6)=6/9=2/3

x/3=k      x=3k
2y/3=k    y=3k/2

3k+3k/2=180⁰
6k+3k=360⁰
9k=360⁰
k=40⁰

x=3*k=3*40=120⁰
y=3k/2=3*40/2=60⁰

Answer 2

0,(3)=3/9=1/3         0,(6)=6/9=2/3U1+U2=180 grade    2/3*U1=1/3*U2    ⇒2U1=U2      ⇒   U1+2U1=180  ⇒ U1=60,  U2=120