Question

determina masurile a doua unghiuri suplementare care sunt invers proportionale cu 0,[3] respectiv 0,[6]

Answer 1

a+b=180°
0,(3)=3/9=1/3
0,(6)=6/9=2/3
a/3=2b/3    ⇒ b=3a/6=a/2
a+a/2=180°
2a+a=360°
3a=360°
a=120°
b=120°/2=60°