Question

determina media geometrica a numerelor a si b ,daca a= 2radical 3 si b=radical108
Ajutati-ma va rog frumos

Answer 1

a=2$\sqrt{3}$
b=$\sqrt{108}$=6$\sqrt{3}$

Media geometrica este $\sqrt{ab}= \sqrt{2 \sqrt{3}*6 \sqrt{3} } = \sqrt{36} =6$