Question

Determina numarul a din egalitatea: 3+{4x[2+(6+a):3]-7}=24. Multumesc mult !!

Answer 1

$=3+{4[2+\dfrac{6+a}{3}-7}=24$
$3+{8+\dfrac{4(6+a)}{3}-7}=24$
$3+{8+\dfrac{24+4a}{3}-7}=24$
$3+{1+\dfrac{24+4a}{3}=24$
$3+1+\dfrac{24+4a}{3}=24$
$4+\dfrac{24+4a}{3}=24~~~{aduci~la~acelasi~numitor~(3)$
$12+24+4a=24$
$36+4a=72$
$4a=72-36$
$4a=36$
$a=36:4$
$a=\fbox{9}$