Question

Determină numărul de electroni din 2 moli de potasiu.

Answer 1

2,28836•10²⁵ electroni

Date:

$n_K=2 \: mol$

$e⁻=?$

Formulă:

$N=n\cdot N_A$, unde

N=nr. de atomi (atomi)

n=nr. de mol (mol)

$N_A = Numărul \: lui \: Avogadro = 6,022 \cdot {10}^{23} \frac{atomi}{mol}$

Rezolvare:

$N_K = 2 \: mol \cdot 6,022 \cdot {10}^{23} \frac{atomi}{mol} = 12,044 \cdot {10}^{23} atomi \: K = 1,2044 \cdot {10}^{24} atomi \: K$

$Z_K=19 \implies e⁻=19 \implies \: 1 \: atom \: de \: K \: \: are \: \: 19 \: e⁻$

1 at. K……………19 e⁻

1,2044•10²⁴ at. K………………x

x=19•1,2044•10²⁴=22,8836•10²⁴ e⁻=2,28836•10²⁵e⁻