Question

determina numarul natural x din egalitate {[(X-8)×7+6-5]-4}×3-2=10 Va rog ajutatima va dau coroana​

Answer 1

Răspuns:

{[(X-8)×7+6-5]-4}×3-2=10

{[(x-8)x7+6-5]-4}X3=10+2

{[(x-8)x7+6-5]-4}X3=12

{[(x-8)x7+6-5]-4}=12:3

[(x-8)x7+6-5]-4=4

[(x-8)x7+6-5]=4+4

(x-8)x7+6-5=8

(x-8)x7+6=8+5

(x-8)x7+6=13

(x-8)x7=13-6

(x-8)x7=7

(x-8)=7:7

x-8=1

x=1+8

x=9

Answer 2

Răspuns:

sper ca te-am ajutat succes