Question

Determina numarul real x,stiind ca xy+xz-xt=48 si 3y+3z-3t=12

Urgenttttt!!!​

Answer 1

$\it 3y+3z+3t=12 \Rightarrow 3(y+z+t)=12|_{:3} \Rightarrow y+z+t=4\ \ \ \ \ (*)\\ \\ xy+xz+xt=48 \Rightarrow x(y+z+t)=48 \stackrel{(*)}{\Longrightarrow}\ x\cdot4=48|_{:4} \Rightarrow x=12$