Question

Determina numerele direct proportionale cu numerele 3, 5 si 8,daca triplul sumei lor este 96.???

Answer 1

{x,y,z} d.p{3,5,8}=x/3=y/5=z/8=k
x/3=k->x=3k
y/5=k->y=5k
z/8=k->z=8k

3k+5k+8k=3×96
k(3+5+8)=288
16k=288
k=288÷16
k=18

3k=3×18=54
5k=5×18=90
8k=8×18=144
Succes.