Question

determina numerele direct proportionale cu numerele 4,3 si 7,daca media aritmetica a lor este egala cu 28

Answer 1

$\frac{x+y+z}{3}$ = 28

x+y+z=28*3=84

$\frac{x}{4}= \frac{y}{3}= \frac{z}{7} =k$

x=4k
y=3k
z=7k
 introducem in suma

4k+3k+7k=84
14k=84
k=6

x=4*6=24
y=3*6=18
z=7*6=42