Determina numerele naturale a,b,c, daca : a+b+c=223 , 896 : a=7 , b:c=9 rest 5 .
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Răspuns de
2
a+b+c=223
896:a=7 ==> a=896:7=128
b:c=9 rest 5 ==>b=9c+5
Inlocuim :
128+9c+5+c=223
133+10c=223
10c=223-133
10c=90
c=90:9=10
896:a=7 ==> a=896:7=128
b:c=9 rest 5 ==>b=9c+5
Inlocuim :
128+9c+5+c=223
133+10c=223
10c=223-133
10c=90
c=90:9=10
Tiger359:
upsi nu am terminat
Răspuns de
1
∛∛∛[tex]a + b + c= 223 \\ 896:a = 7 =\ \textgreater \ a= 896:7 =\ \textgreater \ a= 128 \\ a+b+c = 223 =\ \textgreater \ 128+b+c=223=\ \textgreater \ b+c=223-128 \\ b+c =95\\ b:c =9...rest...5
=\ \textgreater \ b=9*c+5
\\ b+c =95=\ \textgreater \ 9c+5+c=95=\ \textgreater \ 10c=95-5=\ \textgreater \ 10c=90 \\ =\ \textgreater \ c=90:10=\ \textgreater \ c=9 \\ b=9c+5 =\ \textgreater \ b=9*9+5=\ \textgreater \ b=86[/tex]
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