Question

Determina numerele naturale consecutive xy si xz pentru care xy+xz=145

Answer 1

xy=xz+1
10x+y=10x+z+1
y=z+1

xy+xz=145
10x+y+10x+z=145
20x+z+1+z=145
20x+2z=144
10x+z=72 ⇒ xz=72 ⇒ x=7, z=2, y=z+1=3

numerele consecutive sunt
xy=73
xz=72