Question

Determina numerele naturale n pentru care (n+3) | (5n+29)

|=divide

Answer 1

n+3 | 5n+29
n+3 | n+3=> n+3| 5(n+3)
n+3 | 5n +15

=> n+3 | 5n+29-(5n+15)
n+3 | 5n+29-5n-15
n+3 | 14
n€ N

=> (n+3) € { 1; 2; 7; 14} => n € { 4; 11}