Question

determina pe x {[( X -8) x7 +6-5] -4} x3 -2=10

Answer 1

{[( x -8) ·7 +6-5] -4} ·3 -2=10
{[(x-8)·7+6-5]-4}·3=10+2
[(x-8)·7+6-5]-4=12:3
(x-8)·7+6-5=4+4
(x-8)·7+6=8+5
7x-56=13-6
7x=7+56
x=63:7
x=9