Question

Determina termenul necunoscut din egalitatile:
200 g + 320 cg + a = 2 kg 72 q + 1800 kg - b = 3 t 832 g - 80 dg - c + 24 g

Answer 1

200 g + 320 cg + a = 2 kg

200 g + 3,2 g + a = 2 000 g

203,2 g + a = 2 000 g

a = 2 000 g - 203,2 g

a = 1 796,8 g

____________________

72 q + 1800 kg - b = 3 t

72 q + 18 q - b = 30 q

90 q - b = 30 q

b = 90 q - 30 q

b = 60 q

q = quintal

____________________

Answer 2

200g+320cg+a=2kg

200 g=20 000 cg
2 kg = 200 000 cg

20000 cg + 320 cg + a = 200000 cg
20320 cg + a = 200000 cg
a= 200000 cg - 20320 cg
a=179680 cg

72q+1800 kg -b=3t
72 q=7200 kg
3 t = 3000 kg
7200 kg + 1800 kg - b = 3000 kg
9000 kg - b = 3000 kg
b= 9000 kg - 3000 kg
b= 6000 kg

832g-80dg-c=24g
80 dg=8 g
832 g - 8 g - c = 24 g
824 g - c = 24 g
c=824 g - 24 g
c= 800 g