Question

determinati a astfel incat gractia 12/(a+3) sa fie supraunitara

Answer 1

12/a+3<12/12
a+3<12
a=1,2,3,4,5,6,7,8
a+3=11
a+3=10.
.
.a+3=3

Answer 2

$\frac{12}{a+3}\ \textless \ \frac{12}{12}$
$a+3\ \textless \ 12$

$a+3=11$
$\boxed{a=8}$

$a+3=10$
$\boxed{a=7}$

$a+3=9$
$\boxed{a=6}$

[tex]a+3=8 [/tex]
$\boxed{a=5}$

$a+3=7$
$\boxed{a=4}$

$a+3=6$
$\boxed{a=3}$

$a+3=5$
$\boxed{a=2}$

$a+3=4$
$\boxed{a=1}$

$a+3=3$
$\boxed{a=0}$

$a=${$0,1,2,3,4,5,6,7,8$}