Question

determinati al noualea termen al unei progresii geometrice, stiind ca ratia este egala cu 1/3 si primul termen este 243

Answer 1

=243*(1/3)∧8=243:6561=1/27

Answer 2

$b_{9}= b_{1}*q^8 \\ b_{9}=243*( \frac{1}{3})^8 \\ b_{9}= \frac{243}{243*27} = \frac{1}{27}$