Question

determinati aria ,lungimea si diametrul unui cerc cu raza de:4√2,7,2√5 si 2,1

Answer 1

A=πR²,   L=2πR,    D=2R

1. R = 4√2
A=π×(4√2)²=π×4²×(√2)²=π×16×2=32π
L=2π×4√2=8√2π
D=2×4√2=8√2

2. R = 7
A=π×7²=π×7²=49π
L=2π×7=14π
D=2×7=14

3. R = 2√5
A=π×(2√5)²=π×2²×(√5)²=π×4×5=20π
L=2π×2√5=4√5π
D=2×2√5=4√5

Answer 2

A=πr^2 = π ×(4√2)^2 = 32π
L= 2πr=2×π×(4√2)=8√2π
d= 2×r= 2× 4√2=8√2

A= π × 7^2= 49π
L= 2×π×7=14π
d= 2×π=14

A=π×(2√5)^2=20π
L=2×π×(2√5)=4√5π
d=2×2√5=4√5