Question

determinati cel mai mare divizor comun al urmatoarelor numere naturale 60:48,48:72 ,75:60,72:90,80:120,90:135,144:96,72:1880

Answer 1

Se iau toți factorii primi comuni, la puterile cele mai mici. 
(60, 48) = 2² × 3 = 12
(48, 72) = 2³ × 3 = 24
(75, 60) = 3 ×5 = 15
(72, 90) = 2 × 3²= 18
(80, 120) = 2³ * 5 = 40
90 = 2 * 3² * 5 ;135 = 3³ * 5 ; (90, 135) = 3² × 5 = 45
144 = 2²×2²× 3² ;96 = 2²×2³× 3 ; (144, 96) = 2²×2² × 3 = 48
72 = 2³ × 3² ; 180 = 2² × 3² × 5 ; (72, 180) = 2² × 3² = 36
72;180 daca ii 180 daca ii 1800 e altceva =))