Question

Determinați cel mai mic multiplu comun al următoarelor numere naturale: a 24; 36; b) 28; 42; c) 30; 45; d) 36; 54; 60; 48; ; ; f) 48; 72; g) 75; 60; h) 54; 90; 1972; 108; j) 80; 120; k) 54; 180; 1) 75; 200.​

Answer 1

Răspuns:

24 = 2^3*3

36 = 2^2*3^2

cmmmc = 2^3*3^2 = 72

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b)

28 = 7*2^2

42 = 7*2*3

cmmmc = 7*3*2^2 = 84

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c)

30 = 2*3*5

45 = 3^2*5

cmmmc = 2*3^2*5 = 90

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d)

36 = 2^2*3^2

54 = 2*3^3

cmmmc = 2^2*3^3 = 108

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e)

60 = 2^2*3*5

48 = 2^4*3

cmmmc = 2^4*3*5 = 240

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f)

48 = 2^4*3

72 = 2^3*3^2

cmmmc = 2^4*3^2 = 144

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g)

75 = 3*5^2

60 = 2^2*3*5

cmmmc = 2^2*3*5^2 = 300

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h)

54 = 2*3^3

90 = 2*3^2*5

cmmmc = 2*3^3*5 = 270

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i)

72 = 2^3*3^2

108 = 2^2*3^3

cmmmc = 2^3*3^3 = 216

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k)

54 = 2*3^3

180 = 2^2*3^2*5

cmmmc = 2^2*3^3*5 = 540

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l)

75 = 3*5^2

200 = 2^3*5^2

cmmmc = 2^3*5^2*3 = 600