Question

Determinati cel mai mic nr nat care impartit pe rand la 14 21 si 35 sa dea de fiecare data restul 6 si caturi nenule

Answer 1

a : 14 = x rest 6 ==> a = 14x + 6
a : 21 = y rest 6 ==> a = 21y + 6
a : 35 = z rest 6 ==> a = 35z + 6
14 = 2 × 7
21 = 3 × 7
35 = 5 × 7
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2 × 3 × 5 × 7 = 210
a - 6 = 210
a = 210+6
a = 216 (cel mai mic nr care indeplineste conditiile)

216 : 14 = 15 rest 6
216 : 21 = 10 rest 6
216 : 35 = 6 rest 6