Question

determinati cel mai mic nr natural care impartit pe rand la 14 , 21 si 35 da de fiecare data rest 6 si caturi nenule

Answer 1

x:14=c1 rest 6
x=M₁₄ +6

x:21=c2 rest 6
x=M₂₁ +6

x:35=c3 rest 6
x=M₃₅ +6

x=[M₁₄;M₂₁;M₃₅]+6
x-cel mai mic

14=2*7
21=3*7
35=7*5

[14;21;35]= 2*3*7*5= 30*7=210

x=210+6=216