Question

determinati cel mai mic numar natural care, impartit pe rand la 25 , 20 si 12 da resturile 25 , 19 si 11. 

Answer 1

x:25=a r 25=>x=25a+25
x:20=b r 19=> x=20b+19 }+1
x:12=c r 11 => x=12c+11 }+1

=> x= 25a+25 =>
=> x+1=20(b+1)=>
=> x+1=12(c+1) =>

[25;20;12]=300

x+1 apartine multiplilor lui 300