Question

Determinati cel mai mic numar natural care impartit pe rand la 14,21 si 35 da de fiecare data restul 6 si caturi nenule.

Answer 1

x:14=c1 rest 6
x=14 * c1 +6
x=M14+6

x:21=c2 rest 6
x=21 * c2+6
x=M21+6

x:35=c3 rest 6
x=35* c3 +6
x=M35+6

x=[M14;M21;M35]*c+6

c=1 deoarece se cere cel mai mic numar natural

14=2*7
21=3*7
35=5*7

x=2*3*5*7*1+6
x=10*21+6
x=210+6
x=216