Question

Determinati cel mai mic numar natural care impartit pe rand la 12,15 si 27 da de fiecare data restul 3 si caturi nenule.

Va rooog!!!

Answer 1

x=12c+3   ⇒x-3=12c
x=15c+3⇒   x-3=15c
x=27c+3⇒   x-3=27c

(x-3)∈M[12,15,27]
[12,15,27]=3³·5·2²=540
M540={540, 1080, 1620, 2160........}
x-3=540
x=540+3
x=543
540:12=45 rest 3
543:15=36 rest 3
543:27=20 rest 3
deci nr.cel mai mic care indeplineste cond.este nr.543