Question

Determinati cel mai mic numar natural care impartit pe rand la 14, 21 si 35 da de fiecare data restul 6 si caturi nenule.

Answer 1

x=14c+6  ⇒ x-6=14c
x=21c+6   ⇒x-6=21c
x=35c+6   ⇒x-6=35c

x-6∈M[14,21,35]
[14,21,35]=7·2·3·5=210
M210={210, 420, 630, 840.....}
x-6=210
x=216
216:14=15 rest 6
216:21=10 rest 6
216:35=6 rest6
nr.cel mai mic care indeplineste cond.este nr.216