Question

determinati cel mai mic numar natural diferit de 5 care impartit la 16 , 24 si la 32 da acelasi rest 3

Answer 1

n$\neq 5$

n : 16 = c1 , 3
n : 24 = c2 , 3
n : 32 = c3 , 3
<=>

n=16c1 + 3
n=24c2 + 3
n=32c3 + 3

16 =  $2^{4}$
24 = $2^{3}$ * 3
32 = $2^{5}$

Facem cel mai mic multiplu comun comun
(16 , 24 , 32) = $2^{5}$ * 3 = 96

n = 96 + 3
n = 99