Question

Determinati cifra x pentru care

x8+x0/8x+x9 = 3/4


x8,x0,8x,x9 au bara deasupra

Answer 1

[tex]\it \dfrac{\overline{x8} +\overline{x0}}{\overline{8x}+\overline{x9}} =\dfrac{3}{4} \Rightarrow \dfrac{10x+8+10x}{80+x+10x+9} =\dfrac{3}{4} \Rightarrow \dfrac{20x+8}{11x+89} =\dfrac{3}{4} \Rightarrow \\\;\\ \\\;\\ \Rightarrow 4\cdot(20x+8) = 3\cdot(11x+89) \Rightarrow 80x+32 = 33x +267 \Rightarrow \\\;\\ \\\;\\ 80x-33x = 267-32 \Rightarrow 47x = 235 \Rightarrow x = 5[/tex]