Question

determinati cifrele ditincte a b c stiind ca aa bara deasupra+ba bara deasupra +ca bara deasupra =ab3 bara deasupra
ajutor sau coronita

Answer 1

aa+ba+ca=ab3;
⇒10a+a+10b+a+10c+a=100a+10b+3;
⇒13a+10b+10c=100a+10b+3⇒se reduce 10b cu 10b;
⇒13a+10c=100a+3⇒a=1⇒c=9⇒singura varianta posibila;
⇒13+90=103;
⇒11+b1+91=1b3
⇒102+b1=1b3⇒b=1⇒b≠a⇒1≠1⇒fals⇒b≠1;
⇒b=[2,3,4,5,6,7,8,9];⇒b=9⇒c=9⇒9≠9⇒fals⇒b≠9;
⇒b=[2,3,4,5,6,7,8];
⇒a=1;
⇒c=9;