Determinați compoziția porocentuală elementală pertru
Ca (OH)2; H2SO4;H2O;Fe3O4;PCL5
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Răspunsuri la întrebare
Ca(OH)2
40g Ca.... 32g O ..... 2g H ..... 74g Ca(OH)2
x.....................y................z............100g Ca(OH)2
x=40*100/74=54,05% Ca
y=32*100/74=42,24% O
z = 100 - 42,24 - 54,05 = 3,71% H
H2SO4
2g H..... 32g S...... 64g O........ 98g H2SO4
x..................y...................z..........100g H2SO4
x = 2*100/98 = 2,04% H
y = 32*100/98 = 32,65% S
z = 100 - 2,04 - 32,65 = 65,31% O
H2O
2g H.....16g O.......18g H2O
x............y..............100g H2O
x = 2*100/18 = 11,11% H
y = 100 - 11,11 = 88,89% O
Fe3O4
168g Fe....... 64g O....... 232g Fe3O4
x.........................y................100g Fe3O4
x=168*100/232 = 72,41% Fe
y = 100 - 72,41 = 27,59% O
PCl5
31g P...... 177,5g Cl...... 208,5g PCl5
x.....................y..................100g PCl5
x = 31*100/208,5 = 14,87% P
y = 100 - 14,87 = 85,13% Cl