Question

Determinati compozitia procentuala pentru urmatoarele substante: a) KI b) CaCO3.
URGENT!!!!!!

Answer 1

KI   iodura de potasiu
MKI=39+127=166

166g KI-------39gK-------127gI
100gKI---------x---------------y
x=100.39:166=23,49 la suta K
y=100.127:166=76,5 la suta Iod


CaCO3
MCaCO3=40+12+3.16=100
100gCaCO3--------40gCa-------12gC---------48gO
100gCaCO3--------X----------------Y-----------------Z
X=100.40:100=40 la  suta Ca
y=100.12:100=12 la suta C
Z=100.48:100=48 la suta O



Sper ca ai inteles.