Question

DETERMINATI CONCENTRATIA MOLARA A SOLUTIILOR CARE CONTIN :
A)400G NaOH IN 5L SOLUTIE
B)196G H2SO4 IN 200G SOLUTIE CU p=1,84 G/CM(CM LA A TREIA)

Answer 1

a) n=400/40=10 moli NaOH
C=n/V=10/5=2 M

b)p=m/V
V=m/p=200/1.84=108.69 mL (sau cm3)=0.108 L

n=196/98=2
C=n/V=2/0.108=18.5 M