Question

DETERMINATI COORDONATELE PUNCTELELOR DE INTERSECTIE ALE GRAFICELOR FUNCTIILOR f SI g DACA f:R-R,f(x)=2x^2-2x+3, g:R-R,f(x)=x+12

Answer 1

2x²-2x+3=x+12
2x²-3x-9=0
 x1,2= (3+-√(9+72)/4
x1=(3-9)/4=-6/4=-3/2
x2=(3+9)/4=12/4=3
g(x1) =-3/2+12=21/2
g(x2)=3+12=15
 
deci punctele sunt
P (-3/2; 21/2)
Q(3/15)