Question

Determinati doua numere naturale a si b care verifica egalitatea: [2+(axb + 31x8 -648:3):2]x3+1944=2019

Answer 1

Răspuns:

Explicație pas cu pas:

[2+(a×b+31×8-648÷3)÷2]×3+1944=2019

[2+(a×b+248-216)÷2]×3+1944=2019

[2+(a×b+248-216)÷2]×3=2019-1944

[2+(a×b+248-216)÷2]×3=75

2+(a×b+248-216)÷2=75÷3

2+(a×b+248-216)÷2=25

(a×b+248-216)÷2=25-2

(a×b+248-216)÷2=23

a×b+248-216=23×2

a×b+248-216=46

a×b+248=46+216

a×b+248=262

a×b=262-248

a×b=14

1. a=1; b=14
2. a=14; b=1
3. a=2; b=7
4. a=7; b=2

Answer 2

[2+(a×b+31×8-648:3):2]×3+1944=2019

[2+(a×b+248-216):2]×3=2019-1944

[2+(a×b+32):2]×3=75

2+(a×b+32):2=75:3

2+(a×b+32):2=25

(a×b+32):2=25-2

(a×b+32):2=23

a×b+32=23×2

a×b+32=46

a×b=46-32

a×b=14

a poate fi : 1,2,7,14

b poate fi : 1,2,7,14

a×b=1×14=14×1=2×7=7×2