Question

Determinati doua numere naturale care au suma 103 si impartind unul la celălalt se obține catul 4 si restul 3

Answer 1

$a+b=103$

$a:b=4 \ rest3=\textgreatera=4b+3$

$4b+3+b=103$

$5b=103-3$

$5b=100$

$b=100:5$

$b=20$

$a=4*20+3$

$a=83$

Answer 2

x+y=103=>4y+3+y=103=>5y=103-3=>5y=100=>y=100÷5=>y=20
x÷y=4 r3=>x=4y+3=>4×20+3=83