Question

determinati elementele multimilor A si B stiind ca sunt indeplinite simultan conditiile:A\B={3,7},A intertsectat B={4,5} si AUB={x divide x apartine N(nr nat),2 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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AJUTOR!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!va roggggggg!!
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Answer 1

Pentru urmatoarele date:

$A\setminus B=3,7$
$A\cap B=4,5$
$A\cup B=3,4,5,6,7$
Stim in general ca
$A\setminus B=A-A\cap B$
Asta se intampla pentru ca elementele care sunt scoase din multimea A cand facem diferenta sunt exact acele elemente care sunt comune ambelor multimi

De aici ne dam seama ca elementele multimii A sunt de fapt elementele diferentei dimpreuna cu elementele din intersectie, deci
$A=A\setminus B+A\cap B={3,4,5,7}$ Acel plus pentru multimi inseamna ca unesti doua multimi
dar noi stim ca $A\cup B=3,4,5,6,7$, singurul element din A care nu il vezi acolo este elementul 6, care trebuie sa vina din B
Deci, B=6 pana acum, dar mai stim ca  $A\cap B=4,5$, deci si elementele 4,5 sunt in B

B={4,5,6} 3 si 7 nu sunt in B ca au iesit la diferenta dintre A si B, deci acestea sunt cele doua multimi