Question

Determinati formula chimica a substantei 28,57℅ mg 14,29℅ c si rest 0

Answer 1

M,Mg= 24g/mol

n=m/.M= 28,57/24=> 1,19molMg

M,C= 12g/mol

n= 14,29/12=>1,19molC

M,O= 16g/mol

n=(100-28,57-14,29)/16=>3,57molO

RAPORTUL MOLAR : 1,19:1,19:3,57 SIMPLIFICAT CU 1.19->

1: 1: 3----> FORMULA CHIMICA MgCO3