Question

Determinati formula procentuala a Co2

Doresc rezolvara exact asa cum se face in clasa a VII-a, va rog.

Multumesc.

Answer 1

1. calculam masa moleculara a substantei:

CO2

M(CO2) = 1x12+3x16 = 44 g/mol

2.  in masa moleculara intelem ca

in 44 g CO2 ...............avem ..12 g C ... si ... 2x16g O

dar la 100% (100 g CO2) ... a% C ................ b% O

=: a = 12x100/44 = 27,27% C

b+ 32x100/44 = 72,73% O

deci 27,27% C + 72,73% O = 100% CO2

sper sa-ti fie pe inteles...