Question

Determinati formula procentuala a urmatoarelor grupari chimice : VA ROG (URGENT MAINE MA ASCULTA MERSI)
NaOH
H3PO4
MgSO4
Ca(NO3)2
H3PO3

Answer 1

Na OH

M=23+16+1=40

40 g NaOH-------23 g Na------16 g O----1gH
100gNaOH--------X---------------y------------z
x=100.23:40=57,50 la suta Na
y=100.16:40=40 la suta O


H3PO4

M=3+31+4.16=98

98 g H3PO4------3g H-------31 g P--------64 g O
100 g H3PO4-----X-------------Y--------------Z

X=100.3:98=3,06 la suta H
Y=100.31:98=31,63 la suta P
Z=100.64:98=63,3 la suta O
Z=100.1:40=2,5 la suta H


MgSO4
M=24+32+4.16=120

120g MgSO4--------24 g Mg--------32 gS---------64 g O
100gMgSO4-----------X---------------Y-----------------Z

X=100.24:120=20 la suta Mg
y=100.32:120=26,6 la suta S
Z=100.64:120=53,33 la suta O


Ca(NO3)2

MCa(NO3)2=40+2.14+6.16=164

164gCa(NO3)2------40 g Ca--------28g N--------96 gO
100--------------------------X--------------Y-------------Z
X=100.40:164=24,39 la suta Ca
y=100.28:164=17,07 la suta N
Z=100.96:164=58,53 la suta O


H3PO3
M=3+31+3.16=82

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