Question

determinati imaginea functiei x² +x-1​

Answer 1

$x^{2} +x-1=0\\a=1\\b=1\\c=-1\\Delta=b^{2}-4ac=1-4*1(-1)=1-(-4)=5\\Imaginea functiei=[\frac{-delta}{4a}=\frac{-5}{4};,+infinit) = > Imgf=[\frac{-5}{4} ;+infinit)$