Question

determinati in care dintre bazele de mai jos procentul de oxigen este mai mare:
a) Fe(OH)3 (hidroxid de fier)
b) Al(OH)3 (hidroxid de aluminiu)
c) NaOH (hidroxid de sodiu)

plsss coroana​

Answer 1

Răspuns:

Al(OH)3 (hidroxid de aluminiu)

Explicație:

M Fe(OH)3 = 107 g/mol

M Al(OH)3 = 78 g/mol

M NaOH = 40 g/mol

107 g Fe(OH)3.............................48 g oxigen

100 g..............................................x = 100*48/107 = 44,9%

78 g Al(OH)3............................48 g oxigen

100 g.........................................y = 48*100/78 = 61,5%

100 g NaOH..............................16 g oxigen

40 g...............................................z = 40*16/100 = 6,4%