Question

determinati in fiecare caz numerele x stiind ca (2×x+1) bara 7

Answer 1

a)(2•x+1)/7
2•x+1€D7(divizorii lui7)
2•x+1 € {1;7}
2•x+1=1 |-1
2x=0 |:2
x=0
2•x+1=7 |-1
2x=6 |:2
x=3
x € {0;3}

b)3•x+1/16
3•x+1 € D16
3•x+1 € {1;2;4;8;16}
3•x+1=1 |-1
3x=0 |:3
x=0
3•x+1=2 |-1
3x=1 |:3
x=0,(3)
3•x+1=4 |-1
3x=3 |:3
x=1
3•x+1=8 |-1
3x=7 |:3
x=2,(3)
3•x+1=16 |-1
3x=15 |:3
x=5
x € {0;0,(3),1,2,(3),5}

Nu cred că e bine, dar am încercat! Sorry!!!